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Team total points odd/even strategy | დესა

Team total points odd/even strategy

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The chances that the points scored by a team at a game to be strange or even are the same as the odds of head and tail to come out once we flip the coin, meaning 50 percent. Notably in sports like basketball the points occur more than one at one time and also where the scores are large. It’s just a game of numbers.
We knoe that the probability for each result is 50% and if we understand we can use the laws of distribution to estimate the odds of events to happen in trials.
What I mean is that if a group has 6 consecutive odd total points, the odds that the 7th match that the points considered to be strange are 0.062, 62 out of 1000. More if a team has 7 consecutive odd total points that the chances to get at the 8th are 0.035, 35 from 1000. The probability will not become 0 after 8 or 9 consecutive odds but they’re getting more closer to 0. Even there still are opportunities to replicate, but just 35 in 1000 trilas.
The main point is that Dallas Mavericks possess 6 successive odd total points so if we bet total points even for Dallas the chances to eliminate the wager are 6.2% and Phoenix Suns have 7 consecutive odd totals so if we they will score tonight that a total even the odds to shed are 3.5 percent.
I didn’t earn any backtesting so I will take them as two bets but it’s pure math.

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